You cannot use super.super.method() to call a method from a grandparent class. Java does not support this level of direct access.
You meant: — but that doesn’t align.
| Feature | Rating | Notes | |---------|--------|-------| | CLI ease | ⭐⭐⭐⭐ | Runs like top but for JVM | | Metrics | ⭐⭐⭐ | CPU, heap, non-heap, class count | | Thread view | ⭐⭐⭐ | Shows top threads by CPU | | Installation | ⭐⭐ | Requires manual download, not in package managers | | Active maintenance | ❌ | Last update 2017 (JDK 8 era) |
In generic classes, super is also used as a (e.g., List<? super Integer> ). While not directly related to the super keyword, it’s a common source of confusion. Remember: sup java com top
Mastering the Super Keyword in Java: A Comprehensive Guide to Parent Class Access
/** * Opens an existing workbook. * @param filePath absolute path to .xlsx file */ public void openWorkbook(String filePath) Dispatch source = Dispatch.call(workbooks, "Open", filePath).toDispatch(); workbook = source; sheet = Dispatch.get(workbook, "ActiveSheet").toDispatch();
Our parent class will have a constructor, a field, and a method. We’ll use protected visibility so that child classes can access members (though super works with private as well via getters). You cannot use super
The super keyword is indispensable for creating robust, well-organized code.
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# From the directory containing the 'com' folder javac com/top/*.java java com.top.TopChild | Feature | Rating | Notes | |---------|--------|-------|
Download the Microsoft Program Install and Uninstall Troubleshooter. Run it to forcefully purge older remnants of the Java Runtime Environment (JRE). Alternatively, perform an offline installation using the standalone executable rather than the web-based wrapper. Managing the Exception Site List (Grayed-Out Add Button)
class Dog extends Animal @Override void speak() super.speak(); // call parent method first System.out.println("Dog barks");